29/32 as a decimal
29/32 = 0.90625 inches = 23.0187 mm.
0.90625
29/32 of an inch
Millimetres
23.0187 mm
Centimetres
2.30187 cm
Percent
90.625%
Decimal
terminates
Where 29/32 falls at each precision, and whether the mark is the value exactly
| Rule | Nearest mark | Exact? |
|---|---|---|
| 1/16 | 15/16 | nearest |
| 1/32 | 29/32 | exact |
| 1/64 | 29/32 | exact |
29/32 = 58/64
All the same mark. 29/32 is the form in lowest terms, which is how a rule labels it and how a cut list should read.
Converting 29/32 to a decimal
A fraction is a division. 29/32 = 29 ÷ 32 = 0.90625. The decimal terminates because 32 factors into 2 × 2 × 2 × 2 × 2 — only 2s and 5s, the factors of ten. Any fraction whose denominator is built from those has an exact decimal.
In metric that is 23.0187 millimetres (2.30187 cm), since one inch is exactly 25.4 mm. As a percentage of an inch it is 90.625%.
29/32 is a real mark on a rule: it is the 29/32 mark on a 1/32 rule, and the same mark is written 58/64 at finer precisions.
Going the other way
To turn 0.90625 back into a fraction, pick the precision you are working to and multiply. At 1/16: 0.90625 × 16 = 14.5, giving 15/16 after rounding to the nearest mark. At 1/32: 0.90625 × 32 = 29, giving 29/32 exactly. At 1/64: 0.90625 × 64 = 58, giving 29/32 exactly.
What is 29/32 as a decimal?
29/32 as a decimal is 0.90625. Divide the numerator by the denominator: 29 ÷ 32 = 0.90625. The division comes out exactly, with no remainder left over.
What is 0.90625 as a fraction?
0.90625 as a fraction is 29/32, in lowest terms. It can also be written 58/64, which are the same value expressed over a larger denominator.
How many millimetres is 29/32 of an inch?
29/32 of an inch is 23.0187 mm, or 2.30187 cm. An inch has been defined as exactly 25.4 mm since 1959, so this conversion is a definition rather than a measurement — the millimetre value is exact too.
Where is 29/32 on a tape measure?
29/32 is a real mark on a rule: it is the 29/32 mark on a 1/32 rule, and the same mark is written 58/64 at finer precisions.